And if your math is rusty enough that the additional layers of referential obfuscation in the aftercomic are opaque to you, remember that by the definitions of e and ln( ),

e^{\ln (x)} = x

Also of course

\sqrt{x^{2}} = x

So since by definition τ/π = 2, the expression

\sqrt{{(e^{\ln (\frac{τ}{π})})}^{2}}

is just a ris just a repeatedly-obfuscated way of saying "two".